# Anuj had some chocolates, and he divided them into two lots A and B. He sold the first lot at the rate of ₹2 for 3 chocolates

ago in Maths
Anuj had some chocolates, and he divided them into two lots A and B. He sold the first lot at the rate of ₹2 for 3 chocolates and the second lot at the rate of ₹1 per chocolate, and got a total of ₹400. If he had sold the first lot at the rate of ₹1 per chocolate, and the second lot at the rate of ₹4 for 5 chocolates, his total collection would have been ₹460. Find the total number of chocolates he had.

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Solution:

Let the number of chocolates in lot A be x

And let the number of chocolates in lot B be y

∴ total number of chocolates =x+y

Price of 1 chocolate = ₹ 2/3, so for x chocolates = 2/3 x

and price of y chocolates at the rate of ₹ 1 per chocolate =y.

∴ by the given condition 2/3 x +y=400

⇒2x+3y=1200 ..............(i)

Similarly x+ 4/5 y = 460

⇒5x+4y=2300 ........ (ii)

Solving (i) and (ii)

we get x=300 and y=200

∴x+y=300+200=500

So, Anuj had 500 chocolates.